3(x^2/9)^2-27x=0

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Solution for 3(x^2/9)^2-27x=0 equation: 



3(x^2/9)^2-27x=0

We add all the numbers together, and all the variables

-27x+3(x^2/9)^2=0

We multiply all the terms by the denominator


-27x*9)^2+3(x^2=0

Wy multiply elements

-243x^2=0

a = -243; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-243)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-486}=0$

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